0=-16x^2+7x+10

Solution for 0=-16x^2+7x+10 equation:

0=-16x^2+7x+10

We move all terms to the left:

0-(-16x^2+7x+10)=0

We add all the numbers together, and all the variables

-(-16x^2+7x+10)=0

We get rid of parentheses

16x^2-7x-10=0

a = 16; b = -7; c = -10;
Δ = b2-4ac
Δ = -72-4·16·(-10)
Δ = 689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{689}}{2*16}=\frac{7-\sqrt{689}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{689}}{2*16}=\frac{7+\sqrt{689}}{32}
$